Question

How do you evaluate the limit `sin(6x)/6` as x approaches `0`?

Answer 1

`0`

Explanation:

Our first step, when evaluating these limits algebraically, should be to plug in the value we're approaching:

`lim_(x->0)sin(6x)/6=sin(6*0)/6=sin(0)/6`

With this problem, no further simplification or rewriting is necessary.

`sin(0)=0,` so we get

`=0/6=0`