Question

How do you evaluate the limit `sqrt(3-3x)` as x approaches `1^-`?

Answer 1

`0`

Explanation:

The square root of zero is defined.

`:.`

`sqrt(0)=0`

Plugging in `x=1`

`sqrt(3-3(1))=sqrt(0)=0`

`lim_(x->1^-)(sqrt(3-3x))=0`