How do you evaluate the limit #(sqrt(x^2+7)-3)/(x+3)# as x approaches 3?
1 Answer
Oct 6, 2016
Explanation:
Since the function is not indeterminate when x = 3, we can evaluate the limit by direct substitution.
#rArrlim_(xto3)(sqrt(x^2+7)-3)/(x+3)#
#=(sqrt(3^2+7)-3)/(3+3)=(4-3)/6=1/6#
