Question

How do you evaluate the limit `x/(1+4x^2)` as x approaches `oo`?

Answer 1

`lim_(xrarroo) x/(1+4x^2)=0`

Explanation:

`lim_(xrarroo) x/(1+4x^2)`

after dividing the numerator and denominator by `(x^2)`
`color(white)("XXX")=lim_(xrarroo) (1/x)/(1/(x^2)+4)`

`color(white)("XXX")=0/(0+4)`

`color(white)("XXX")=0`