How do you evaluate the polynomial #-3x^3+8x^2-4x-6# for #x=4# and for #x=-4#?
1 Answer
Jun 24, 2018
Explanation:
#"substitute the given values for x into the expression"#
#-3xx(color(red)(4))^3+8xx(color(red)(4))^2-4xxcolor(red)(4)-6#
#=(-3xx64)+(8xx16)+(-4xx4)-6#
#=-192+128-16-6#
#=-86#
#-3xx(color(red)(-4))^3+8xx(color(red)(-4))^2-4xxcolor(red)(-4)-6#
#=(-3xx-64)+(8xx16)+(-4xx-4)-6#
#=192+128+16-6#
#=330#