How do you evaluate #w-3x+y# if w=6, x=0.4, y=1/2, z=-3?

1 Answer
Dec 23, 2016

Answer:

#color(magenta)(4.3)#

Explanation:

If #color(red)w=color(red)6#
and #color(blue)x=color(blue)(0.4)#
and #color(green)y=color(green)(1/2#

then #color(red)w-3color(blue)x+color(green)y#

#color(white)("XX")=color(red)(6)-3 xx (color(blue)0.4) +color(green)(1/2)#

#color(white)("XX")=5-1.2+0.5#

#color(white)("XX")=3.8 +0.5#

#color(white)("XX")=4.3#