How do you evaluate #w(8-y)# if w=6, x=0.4, y=1/2, z=-3?

1 Answer
Jun 3, 2017

Answer:

See a solution process below:

Explanation:

First, the #x# and #z# terms are not used in the expression so are extraneous to this problem

To evaluate the expression as required in the problem substitute #color(red)(6)# for #color(red)(w)# and substitute #color(blue)(1/2)# for #color(blue)(y)# and then calculate the result:

#color(red)(w)(8 - color(blue)(y))# becomes:

#color(red)(6)(8 - color(blue)(1/2)) =>#

#(color(red)(6) * 8) - (color(red)(6) * color(blue)(1/2)) =>#

#48 - 3 =>#

#45#