Question

How do you evaluate `w(8-y)` if w=6, x=0.4, y=1/2, z=-3?

Answer 1

See a solution process below:

Explanation:

First, the `x` and `z` terms are not used in the expression so are extraneous to this problem

To evaluate the expression as required in the problem substitute `color(red)(6)` for `color(red)(w)` and substitute `color(blue)(1/2)` for `color(blue)(y)` and then calculate the result:

`color(red)(w)(8 - color(blue)(y))` becomes:

`color(red)(6)(8 - color(blue)(1/2)) =>`

`(color(red)(6) * 8) - (color(red)(6) * color(blue)(1/2)) =>`

`48 - 3 =>`

`45`