How do you evaluate #(x - 2) ^ { 3} ( x - 5) ( x - 4) ^ { 2} = 0#?

1 Answer
Alan P.
Sep 4, 2017

#x in {2,5,4}#

Explanation:

If #color(blue)A xx color(green)B xx color(brown)C =0#
then
either #color(blue)A=0#
or #color(white)("xxx")color(green)B=0#
or #color(white)("xxx")color(brown)C=0#

So
if #color(blue)((x-2)^3) * color(green)(""(x-5)) * color(brown)((x-4)^2)=0#
then
either #color(blue)((x-2)^3)=0color(white)("xxx")rarrcolor(white)("xxx")x=2#
or #color(white)("xxx")color(green)(x-5)=0color(white)("xxxxx")rarrcolor(white)("xxx")x=5#
or #color(white)("xxx")color(brown)((x-4)^2)=0color(white)("xxx")rarrcolor(white)("xxx")x=4#

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