# How do you evaluate x^2+3x-5 for x=2?

${2}^{2} + 3 \left(2\right) - 5 = 5$

#### Explanation:

We take the equation:

${x}^{2} + 3 x - 5$

and substitute 2 for $x$:

${2}^{2} + 3 \left(2\right) - 5$

$4 + 6 - 5$

$5$