How do you evaluate $x^2+9x-36$ with x=-13?

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Answer 1 · 2017-01-05T10:33:52

$16$

To evaluate the expression, substitute x = - 13 in for x.

$rArrx^2+9x-36$

$=(color(red)(-13))^2+(9xxcolor(red)(-13))-36$

$=169-117-36=16$

How do you evaluate x^2+9x-36x^2+9x-36 with x=-13?