How do you evaluate #x^2+9x-36# with x=-13?
1 Answer
Jan 5, 2017
Explanation:
To evaluate the expression, substitute x = - 13 in for x.
#rArrx^2+9x-36#
#=(color(red)(-13))^2+(9xxcolor(red)(-13))-36#
#=169-117-36=16#
