Question

How do you evaluate `(x+2)(x+3)(2/(x+2)) = -x/((x+2)(x+3))(x+2)(x+3)`?

Answer 1

`x = - 2`

Explanation:

Well the question appearance may look difficult but it's quite easy..

Just eliminate the common factors and it will make the equation simpler to solve..

`(x + 2) (x + 3) (2/(x + 2)) = - x/((x + 2) (x + 3)) (x + 2) (x + 3)`

Eliminating the common terms

`cancel(x + 2) (x + 3) (2/cancel(x + 2)) = - x/cancel((x + 2) (x + 3)) cancel((x + 2) (x + 3))`

`rArr (x + 3) (2) = - x`

`rArr 2x + 6 = - x`

`rArr 2x + x = - 6`

`rArr 3x = - 6`

`rArr x = - 6/3`

`rArr x = - 2`