How do you evaluate # ((x^2)-x-6)/(x-3)# as x approaches 3?
1 Answer
Sep 20, 2016
5
Explanation:
direct substitution yields
#0/0" indeterminate"# Factorising the function.
#rArr(cancel((x-3))(x+2))/cancel((x-3))=x+2#
#rArrlim_(xto3)(x^2-x-6)/(x-3)=lim_(xto3)(x+2)=5#
