How do you evaluate #x^-3# for #x=2#?
1 Answer
Apr 20, 2018
Explanation:
#"using the "color(blue)"law of exponents"#
#•color(white)(x)a^-mhArr1/a^m#
#rArr2^-3=1/2^3=1/8#
#"using the "color(blue)"law of exponents"#
#•color(white)(x)a^-mhArr1/a^m#
#rArr2^-3=1/2^3=1/8#