How do you evaluate #x-:4+3y^2# for #x=8# and #y=3#?
1 Answer
Jul 20, 2017
Explanation:
#"substitute given values into the expression"#
#x/4+3y^2#
#=color(red)(8)/4+3xxcolor(magenta)(3)^2#
#=2+27#
#=29#
