How do you evaluate $x =_{6} P_{3}$ $x= _6P_3$ ?

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Answer 1 · 2014-11-04T15:10:56

$P (6, 3) = \frac{6!}{(6 - 3)!}$ $P(6, 3) = (6!) / ((6 - 3)!)$

$\Rightarrow P (6, 3) = \frac{6!}{3!}$ $=> P(6, 3) = (6!) / (3!)$

$\Rightarrow P (6, 3) = \frac{6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}{3 \cdot 2 \cdot 1}$ $=> P(6, 3) = (6 * 5 * 4 * 3 * 2 * 1) / (3 * 2 * 1)$

$\Rightarrow P (6, 3) = 6 \cdot 5 \cdot 4$ $=> P(6, 3) = 6 * 5 * 4$

$\Rightarrow P (6, 3) = 120$ $=> P(6, 3) = 120$

Answer 2 · 2014-11-04T15:12:11

$_{6} P_{3} = 6 \cdot 5 \cdot 3 = 90$ $""_6P_3=6cdot5cdot3=90$

(Note: 6 is the factor, and 3 is the total number of factors.)

I hope that this was helpful.

How do you evaluatex=6P3x= _6P_3?