How do you evaluatex= _6P_3?

Nov 4, 2014

 P(6, 3) = (6!) / ((6 - 3)!)

=> P(6, 3) = (6!) / (3!)

$\implies P \left(6 , 3\right) = \frac{6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}{3 \cdot 2 \cdot 1}$

$\implies P \left(6 , 3\right) = 6 \cdot 5 \cdot 4$

$\implies P \left(6 , 3\right) = 120$

Nov 4, 2014

""_6P_3=6cdot5cdot3=90

(Note: 6 is the factor, and 3 is the total number of factors.)

I hope that this was helpful.