# How do you evaluate (x+y)^3 for x=22 and y=5?

Jan 10, 2017

You substitute $\textcolor{red}{22}$ for $x$ and $\textcolor{b l u e}{5}$ for $y$ and the calculate the value:
${\left(\textcolor{red}{x} + \textcolor{b l u e}{y}\right)}^{3}$ with substitution becomes:
${\left(\textcolor{red}{22} + \textcolor{b l u e}{5}\right)}^{3} = {27}^{3} = 27 \times 27 \times 27 = 729 \times 27 = 19 , 683$