How do you evaluate #z- 32= 40#?

1 Answer
Feb 25, 2017

#z = 72#

Explanation:

In the equation #z-32 =40# you want to isolate the #z#

To do this you have to get rid of #-32# which you can do if you add #32#. But in an equation you have to do the same to both sides else you are changing its value.

#z-32+32 =40+32" "larr# simplify both sides

#z = 72#