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How do you evalute $log_5 (1/25)$ ?

1 Answer

Dec 10, 2015

$color(white)(xx)-2$

Explanation:

$color(white)(xxx)log_5(1/25)=log_5(1/5^2)$
$color(white)(xxxxxxxxxx)=log_5(5^-2)$
$color(white)(xxxxxxxxxx)=-2*log_5 5$
$color(white)(xxxxxxxxxx)=-2$

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