How do you expand #2/5(3x-7)#?

1 Answer
Tony B
Apr 16, 2016

#6/5x-14/5#

Explanation:

Multiply everything inside the bracket by #2/5# so we have

#(2/5xx3x)-(2/5xx7)#

Think of the 3 as #3/1# and the 7 as #7/1# which is correct but not normally written this way

#(2/5xx3/1x)-(2/5xx7/1)#

#(2xx3)/(5xx1)x -(2xx7)/(5xx1)" "=" "6/5x-14/5#

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