How do you expand and simplify #sqrt3(6-sqrt12)#?

1 Answer
Dylan D.
Apr 27, 2017

#6sqrt(3)+-6#

Explanation:

distribute the #sqrt(3)#

#sqrt(3)(6) - sqrt(12)sqrt(3)#
#6sqrt(3) - sqrt(12*3)#
#6sqrt(3) - sqrt(36)#
#6sqrt(3) +- 6#

Lessons here:

  • #sqrt(a)sqrt(b) = sqrt(a*b)#, (so long as a and b are not negative)
  • Other than that, this is simple distributive property.
  • Remember the #+-#
Related questions
Impact of this question
988 views around the world
You can reuse this answer
Creative Commons License