How do you expand # ln(x/y) - 2ln(x^3) -4lny #?

1 Answer
May 19, 2016

Answer:

Answer:
after expanding #-5lnx-5lny#
after simplication #-ln(xy)^5#

Explanation:

#ln(A/B) = ln A - ln B#
#ln(AB) = lnA+lnB#
#ln(A^B) = B*lnA#

Using the above two rules we can expand the given expression into:

#lnx - lny -2*3*lnx-4lny#
#rArrlnx-lny-6lnx-4lny#
#or, -5lnx-5lny#

On further simplification we get

#-5(lnx +lny)#
#or-5*lnxy#
#or-ln(xy)^5#