# How do you expand log_3 48?

${\log}_{3} 48 = 1 + 4 {\log}_{3} 2$
Note that $48 = 3 \cdot {2}^{4}$
So: ${\log}_{3} 48 = {\log}_{3} \left(3 \cdot {2}^{4}\right) = {\log}_{3} 3 + {\log}_{3} \left({2}^{4}\right) = 1 + 4 {\log}_{3} 2$