Question

How do you expand `log ([sqrt(x+1)]/(x^2+1))`?

Answer 1

`log ((sqrt(x+1))/(x^2 +1))` `=1/2 log(x+1)-log(x^2+1)`

Explanation:

`log ((sqrt(x+1))/(x^2 +1))`

`=logsqrt(x+1) - log (x^2+1)`-> use property `log_b(x/y)=log_bx-log_by`

`=log(x+1)^(1/2) -log(x^2+1)`

`=1/2 log(x+1)-log(x^2+1)`