How do you expand #log ((x^4)/(x-2))#?

1 Answer
May 25, 2016

Answer:

#4logx - log(x-2)#

Explanation:

Remember logs are indices, so the same rules apply.
If you are dividing two numbers, (as in this case) then subtract their logs.

#log[x^4 ÷ (x-2)] = logx^4 - log(x-2)#
Using the power law:

#4logx - log(x-2)#