Question

How do you expand the logarithmic expression `ln (x/3y)`?

Answer 1

`ln(x/3y)=lny+lnx-ln3`

Explanation:

Use the fact that `ln(ab)=lna+lnb` and that `ln(a/b)=lna-lnb` to get that `ln(x/3y)=lny+ln(x/3)=lny+lnx-ln3`.