How do you expand this logarithm?

#log_(9)(zsqrtx*y)#

2 Answers
Nov 26, 2016

Answer:

This is the best I got...

Explanation:

Try to use the product of the arguments to change it into a sum of logs as:
#log_9(zsqrt(x)*y)=log_9(z*sqrt(x))+log_9(y)=# and again:
#=log_9(z)+log_9(sqrt(x))+log_9(y)#

Nov 27, 2016

#log_9sqrtx=log_9x^(1/2)=1/2log_9x#