How do you express #(1.8*10^-2)-:(9*10^2)#?

1 Answer
May 29, 2017

See a solution process below:

Explanation:

First, we can rewrite this expression as:

#(1.8 * 10^-2)/(9 * 10^2)#

Next, we can rewrite this expression again as:

#(1.8/9) * ((10^-2)/(10^2))#

#0.2 * ((10^-2)/(10^2))#

Then, we can use this rule of exponents to simplify the 10s term:

#x^color(red)(a)/x^color(blue)(b) = x^(color(red)(a)-color(blue)(b))#

#0.2 * (10^color(red)(-2)/10^color(blue)(2)) => 0.2 * 10^(color(red)(-2)-color(blue)(2)) => 0.2 * 10^-4#

If we want to expression this in true scientific notation we must move the decimal point one place to the right which means we must subtract #1# from the 10s exponent:

#0.2 * 10^-4 => 2.0 * 10^-5#

If we want to express this in standard form we need to move the decimal point 5 places to the left because the 10s exponent is negative:

#2.0 * 10^-5 => 0.00002#