How do you express #(3x)/((x + 2)(x - 1))# in partial fractions?
1 Answer
Aug 10, 2016
Explanation:
#(3x)/((x+2)(x-1)) = A/(x+2)+B/(x-1)#
Use Heaviside's cover-up method to find:
#A = (3(-2))/((-2)-1) = (-6)/(-3) = 2#
#B = (3(1))/((1)+2) = 3/3 = 1#
So:
#(3x)/((x+2)(x-1)) = 2/(x+2)+1/(x-1)#
