# How do you express #(3x)/((x + 2)(x - 1))# in partial fractions?

##### 1 Answer

Aug 10, 2016

#### Explanation:

#(3x)/((x+2)(x-1)) = A/(x+2)+B/(x-1)#

Use Heaviside's cover-up method to find:

#A = (3(-2))/((-2)-1) = (-6)/(-3) = 2#

#B = (3(1))/((1)+2) = 3/3 = 1#

So:

#(3x)/((x+2)(x-1)) = 2/(x+2)+1/(x-1)#