Question

How do you express `4x i+5yi^8+6x i^3+2yi^4` in simplest `a + bi` form?

Answer 1

Remember you may always use `i^2=-1`

Explanation:

Now rewrite:
`=4x*i+5y*(i^2)^4+6x*i^2*i+2y*(i^2)^2`
`=4x*i+5y*(-1)^4+6x*(-1)* i+2y*(-1)^2`
`=4x*i+5y-6x* i+2y`
`=5y+2y+4x i-6x i`

`=7y-2x i`