How do you express #9.01 times 10^-2# in standard form?

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Answer 1 · 2017-05-22T08:13:17

The negative index of #10# indicates that you are dividing by 10, twice:

#9.01 xx 10^-2 = 9.01 div 10 div 10#

#= 0.0901#

OR

You can write this as a fraction:

#9.01 xx 10^-2 = 9.01 xx 1/10^2 = 9.01 xx1/100#

#=0.0901#

OR

You can simply apply the rule which says move the decimal point to the left by #2# places.

#9.01 xx10^-2 = 0.0901#