How do you express in terms of ln2 and ln3 given #ln sqrt13.5#?
1 Answer
Jul 3, 2016
Explanation:
#ln sqrt(13.5) = ln sqrt(3^3/2)#
#= 1/2 ln (3^3/2)#
#= 1/2(ln 3^3 - ln 2)#
#= 1/2( 3 ln 3 - ln 2)#
#= 3/2ln3 - 1/2ln2#
