# How do you express log_4 (1.6)^2 in terms of common logarithms?

${\log}_{4} {\left(1.6\right)}^{2} = 2 {\log}_{10} \frac{1.6}{\log} _ 10 \left(4\right) = 2 \ln \frac{1.6}{\ln} \left(4\right)$