How do you express $log_5 20$ in terms of common logarithms?

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Answer 1 · 2016-12-20T08:52:59

$log_(5)20=log20/log5$

let $" "y=log_(5)20$

$=>5^y=20$

take logs to base 10 on both sides

$log5^y=log20$

$ylog5=log20$

$y=log_(5)20=log20/log5$

How do you express log_5 20log_5 20 in terms of common logarithms?