Question

How do you express `log_5 20` in terms of common logarithms?

Answer 1

`log_(5)20=log20/log5`

Explanation:

let`" "y=log_(5)20`

`=>5^y=20`

take logs to base 10 on both sides

`log5^y=log20`

`ylog5=log20`

`y=log_(5)20=log20/log5`