How do you express #log_5 8# in terms of common logs?

1 Answer
Mar 13, 2017

Answer:

I tried to change base:

Explanation:

We can change base using the formula:
#log_ax=(log_bx)/(log_ba)#
Where #b# is the new base. We can chose a new base such as #10# that can be easily evaluated using a normal pocket calculator.
We get:

#(log_(10)8)/(log_(10)5)=1.292#