How do you express $log_50 23$ in common logarithms?

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Answer 1 · 2016-10-31T16:21:57

$log_50(23) = log_10(23)/log_10(50) = ln(23)/ln(50)$

Use the identity $log_c(a) = log_b(a)/log_b(c)$

The logarithms commonly found on calculators are base 10, $log_10$ , and base e, $ln$

$log_50(23) = log_10(23)/log_10(50) = ln(23)/ln(50)$

How do you express log_50 23log_50 23 in common logarithms?