Question

How do you express `\log _ { 6} 11z` as the sum or difference of logarithms?

Answer 1

`log_6(11) + log_6(z)`

Explanation:

There exists a property of logarithms that states that:

`log_x(a*b) = log_x(a) + log_x(b)`

With this in mind, we can rewrite `log_6(11*z)` as:

`log_6(11) + log_6(z)`