Question

How do you express `log_7 3` in terms of common logarithms?

Answer 1

`=>y=log_(10)3/log_(10)7`

Explanation:

let `y=log_(7)3`

`=>7^y=3`

Take logs to base 10 both sides

`log_(10)7^y=log_(10)3`

`=>ylog_(10)7=log_(10)3`

`=>y=log_(10)3/log_(10)7`