# How do you express the complex number in trigonometric form 2i?

I found: $z = 2 \left(\cos \left(\frac{\pi}{2}\right) + i \sin \left(\frac{\pi}{2}\right)\right)$
It has a modulus (length) of $2$ and argument (angle with positive Re semiaxis) of $\frac{\pi}{2}$.
$z = 2 i = 2 \left(\cos \left(\frac{\pi}{2}\right) + i \sin \left(\frac{\pi}{2}\right)\right)$