How do you express $x^(1/2) / x^(1/3)$ in radical form?

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Answer 1 · 2016-09-04T09:09:59

$root(2)x/root(3)x or root(6)x$

$x^(1/2)/x^(1/3) = x^((1/2-1/3))= x^(1/6)= root(6)x$

Answer 2 · 2016-09-04T09:17:11

$root6 x$

Use the law of indices: $" "x^m/x^n = x^(m-n)$

$x^(1/2)/x^(1/3) = x^(1/2-1/3)$

= $x^((3-2)/6)$

= $x^(1/6)$

Use the law of indices $x^(p/q)= rootq x^p$

= $root6 x$

How do you express x^(1/2) / x^(1/3)x^(1/2) / x^(1/3) in radical form?