How do you express # ( x^2 + 2 ) / (x+2) # in partial fractions?
1 Answer
May 29, 2016
#(x^2+2)/(x+2)= x-2+6/(x+2)#
Explanation:
#(x^2+2)/(x+2)#
#= (x^2+2x-2x-4+6)/(x+2)#
#= (x(x+2)-2(x+2)+6)/(x+2)#
#= x-2+6/(x+2)#
If you prefer, you can long divide the coefficients like this:
Notice the
