How do you express $(x^3+4)/[x^2+4]$ in partial fractions?

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Answer 1 · 2016-05-13T23:32:23

$(x^3+4)/(x^2+4) = x-(4x-4)/(x^2+4)$

$(x^3+4)/(x^2+4) = (x^3+4x-4x+4)/(x^2+4) = x-(4x-4)/(x^2+4)$

The denominator $(x^2+4)$ has no linear factors with Real coefficients since $x^2+4 >= 4 > 0$ for all Real values of $x$ .

How do you express (x^3+4)/[x^2+4] (x^3+4)/[x^2+4] in partial fractions?