# How do you express (x^3+4)/[x^2+4]  in partial fractions?

$\frac{{x}^{3} + 4}{{x}^{2} + 4} = x - \frac{4 x - 4}{{x}^{2} + 4}$
$\frac{{x}^{3} + 4}{{x}^{2} + 4} = \frac{{x}^{3} + 4 x - 4 x + 4}{{x}^{2} + 4} = x - \frac{4 x - 4}{{x}^{2} + 4}$
The denominator $\left({x}^{2} + 4\right)$ has no linear factors with Real coefficients since ${x}^{2} + 4 \ge 4 > 0$ for all Real values of $x$.