# How do you express y=(x-2)^2+4 in standard form?

Jul 23, 2017

See a solution process below:

#### Explanation:

First, square the term in parenthesis using this rule:

${\left(\textcolor{red}{a} - \textcolor{b l u e}{b}\right)}^{2} = {\textcolor{red}{a}}^{2} - 2 \textcolor{red}{a} \textcolor{b l u e}{b} + {\textcolor{b l u e}{b}}^{2}$

$y = {\left(\textcolor{red}{x} - \textcolor{b l u e}{2}\right)}^{2} + 4$

$y = \left({\textcolor{red}{x}}^{2} - \left(2 \cdot \textcolor{red}{x} \cdot \textcolor{b l u e}{2}\right) + {\textcolor{b l u e}{2}}^{2}\right) + 4$

$y = \left({x}^{2} - 4 x + 4\right) + 4$

$y = {x}^{2} - 4 x + 4 + 4$

$y = {x}^{2} - 4 x + 8$