How do you factor #14a^{2} b + 8a b - 6b#?

1 Answer
EZ as pi
Oct 9, 2016

#2b(7a-3)(a+1)#

Explanation:

Always look for a common factor first.
In this case, each term has #2b#
Divide #2b# out of each term.

#2b(7a^2 + 4a - 3)#

Now you have a quadratic trinomial. Check for factors of 7 and 3 which subtract to give 4.
They are both prime numbers, so there are only 2 combinations to try.

#2b(7a-3)(a+1)#

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