How do you factor #16+ 40x ^ { 2} - 25x ^ { 4}#?

1 Answer
Jan 19, 2018

See the explanation below...

Explanation:

These type of polynomials can be factored by substitution.

Let's subtitute #u=x^2# in the above polynomial, so that we get:

#=25u^2+40u+16#

We have to break the #40u# into two terms, let's say #u# and #v# such that their sum must be equal to #40u# and their product must be equal to the product of #25u# and #16#.

Since, #20u+20u=40u# and #20u\cdot 20u = 400u^2#,

we can write:

#=(25u^2+20u)+(20u+16)#

Factor out #5u# from left side terms and #4# from right side terms, so that we get:

#=5u(5u+4)+4(5u+4)#

Factor out common term #(5u+4)#, so that we have left with:

#=(5u+4)(5u+4)#

Substitute back #u=x^2#, and write as a square:

#=(5x^2+4)^2#

Which is our required factored form.