How do you factor #18x ^ { 2} y ^ { 3} z - 24x y ^ { 3} z ^ { 2}#?

1 Answer
Alan N.
Jun 2, 2017

Expression #=6xy^3z(3x-4z)#

Explanation:

Expression #= 18x^2y^3z-24xy^3z^2#

Factoring by constants, then common powers of #x, y, and z# in turn:

Expression #=6(3x^2y^3z-4xy^3z^2)#

#=6x(3xy^3z-4y^3z^2)#

#=6xy^3(3xz-4z^2)#

#=6xy^3z(3x-4z)#

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