How do you factor 24x^{4} + 22x^{3} - 10x^{2}?
2 Answers
Explanation:
There is a
color(blue)"common factor" of2x^2 in all 3 terms.
rArr2x^2(12x^2+11x-5) To factorise the quadratic in the bracket, use the a-c method.
That is consider the factors of - 60 which sum to + 11
These are + 15 and - 4
now write the quadratic expression as.
12x^2-4x+15x-5 and factorise in groups.
color(red)(4x)color(blue)((3x-1))color(red)(+5)color(blue)((3x-1)) Take out the common factor (3x - 1).
rArrcolor(blue)((3x-1))color(red)((4x+5))
rArr12x^2+11x-5=(3x-1)(4x+5) Pulling it all together.
24x^4+22x^3-10x^2=2x^2(3x-1)(4x+5)
Explanation:
In this question we are asked to factor that is to change this algebriac expression into factors .
First,let us check if there is common factor :
As it is shown in blue color the common factor is
Let us calculate
Knowing the Quadratic formula of a quadratic equation
Roots are:
The roots are:
So,