How do you factor #25w^2-30w+9#?

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Answer 1 · 2017-06-27T18:50:40

See a solution process below:

This is a special form of the quadratic:

#(a - b)^2 = a^2 - 2ab + b^2#

Substituting:

#5w# for #a#

#3# for #b#

Gives:

#(5w - 3)^2 = (5w)^2 - (2 * 5w * 3) + 3^2#

#(5w - 3)^2 = 25w^2 - 30w + 9#

Or

#(5w - 3)(5w - 3) = 25w^2 - 30w + 9#