How do you factor #27 - 125x^3?
1 Answer
Feb 22, 2016
Explanation:
This is a
difference of 2 cubes
27−125x3=33−(5x)3 To factor :
a3−b3=(a−b)(a2+ab+b2) For this question let a = 3 and b = 5x
⇒27−125x3=(3−5x)(32+(3×5x)+(5x)2)
=(3−5x)(9+15x+25x2)