How do you factor #27 - 125x^3?

1 Answer
Feb 22, 2016

(35x)(9+15x+25x2)

Explanation:

This is a difference of 2 cubes

27125x3=33(5x)3

To factor : a3b3=(ab)(a2+ab+b2)

For this question let a = 3 and b = 5x

27125x3=(35x)(32+(3×5x)+(5x)2)

=(35x)(9+15x+25x2)