How do you factor #2k ^ { 2} + 12k - 54#?
1 Answer
Oct 26, 2017
Explanation:
#"remove the "color(blue)"common factor of 2"#
#rArr2k^2+12k-54#
#=2(k^2+6k-27)#
#"to factor the quadratic inside the bracket"#
#"the factors of - 27 which sum to + 6 are + 9 and - 3"#
#=2(k+9)(k-3)#
