How do you factor #2t^{3}-14t^{2}+24t#?

Question

840 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-20T14:45:02

#2t(t-3)(t-4)#

#2t^3-14t^2+24t#

Always start by looking for common factors, and if there are
take out the hcfs

#2t(t^2-7t+12)#

the resulting quadratic will factorise if we can find two factors of #+12 # that sum to #-7#

in this case, after trial and error

#-3, #&#-4#

so the complete factorisation is;

#2t(t-3)(t-4)#